Value equal to index value

Given an array, we need to find that element whose value is equal to that of its index value.

Input:

The first line of input contains an integer T denoting the number of test cases.
The first line of each test case is N,N is the size of array.
The second line of each test case contains N input A[].

Output:

Print that element whose value is equal to index value. Print "Not Found" when index value does not match with value.
Note: There can be more than one element in the array which have same value as their index. You need to print every such element's index separated by a single space. Follows 1-based indexing of the array. 

Constraints:

1 ≤ T ≤ 30
1 ≤ N ≤ 50
1 ≤ A[i] ≤ 1000

Example:

Input
2
5
15 2 45 12 7
1
1

Output
2
1

Your Code

#include<iostream>

using namespace std;

int main()

{

int t;

cin>>t;

while(t--)

{

int n;

cin>>n;

int i, a[1000];

int num=0;

for(i=0; i<n; i++)

{

cin>>a[i];

}

for(i=0; i<n; i++)

{

if(a[i]==i+1)

{   num++;

cout<<i+1<<" ";

}

}

if(num==0)

cout<<"Not Found";

cout<<endl;

}

}